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1. Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca (bobjonkmanformer@sn.jonkman.ca)'s status on Saturday, 04-Feb-2017 22:46:04 UTC Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca

   • nybill
   Remind me of the math. How much current can you pull from a 22000uF capacitor with 64V on it?
   • Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca (bobjonkmanformer@sn.jonkman.ca)'s status on Saturday, 04-Feb-2017 23:25:01 UTC Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca

     • Stephen Sekula
     I remember learning that in the Magnetism and Electricity course from Uni, but I don't remember what I actually learned. http://sn.jonkman.ca/attachment/49136
   • Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca (bobjonkmanformer@sn.jonkman.ca)'s status on Saturday, 04-Feb-2017 23:25:57 UTC Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca

     in reply to
     Happily, I still have the text, "Fundamentals of Electricity and Magnetism" by Arthur F. Kip. (c) 1969
   • Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca (bobjonkmanformer@sn.jonkman.ca)'s status on Sunday, 05-Feb-2017 01:20:15 UTC Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca

     • Stephen Sekula
     @steve@chirp.cooleysekula.net That's a lovely analysis! If the leakage could be due to the dielectric's resistance, wouldn't the observed leakage be due to *both* that and the leakage through air? Then the calculated resistance would be that of dielectric and air in parallel...
   • Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca (bobjonkmanformer@sn.jonkman.ca)'s status on Sunday, 05-Feb-2017 01:31:17 UTC Former Bob Jonkman -- Please use the new server at https://gs.jonkman.ca

     • nybill
     And to answer my own question, with R=3.8E7 then the current at the start was 30V/R = about 0.8 uA, and at the end 13V/R = about 0.3 uA